Problem Description
You are given a strictly increasing integer array rungs representing the heights of rungs on a ladder. Starting at the floor (height 0), your goal is to reach the highest rung. You can only move to the next rung if the vertical distance from your current position to the next rung is at most dist. You are allowed to add rungs at any positive integer heights where one does not already exist. Return the minimum number of rungs that need to be added so that you can climb the ladder.
Key Insights
- The problem revolves around ensuring all gaps (between the current position and the next rung) are no larger than the allowed distance dist.
- Start by checking the gap from the ground (height 0) to the first rung.
- For each consecutive rung, if the gap is more than dist, calculate the number of rungs needed to cover this gap.
- The formula (gap - 1) // dist gives the minimal rungs needed for any gap that exceeds dist.
- A greedy approach works here — handle each gap independently to minimize the total additions.
Space and Time Complexity
Time Complexity: O(n) where n is the number of rungs, as we traverse the array once. Space Complexity: O(1) additional space.
Solution
We iterate from the ground (0) to each rung, computing the gap between our current position and the next rung. If the gap exceeds dist, we calculate how many rungs we must add using the formula: additionalRungs = (gap - 1) // dist. This formula captures the idea of breaking the gap into segments of at most dist. Sum these additional rungs across all gaps to get the final count. Data structures used are a simple integer counter and iteration over the array, making this a straightforward greedy approach.