Problem Description
Two players take turns selecting numbers from 1 to maxChoosableInteger without replacement. The selected numbers are added to a running total. The player whose move causes the total to reach or exceed desiredTotal wins. Determine if the first player can force a win, assuming both players play optimally.
Key Insights
- Use recursion (DFS/backtracking) with memoization to evaluate game states.
- Represent each game state with a bitmask tracking which numbers have been chosen.
- Base case: if a chosen number is greater than or equal to the remaining total needed, it results in an immediate win for the current player.
- Check if the sum of all numbers is less than desiredTotal; if so, the game cannot be won.
- At each state, try every available number and let the opponent play optimally; if any move forces the opponent into a losing position, the current player wins.
- The problem uses game theory logic: ensuring that if all subsequent moves lead to opponent’s wins, then current move is losing.
Space and Time Complexity
Time Complexity: O(2^maxChoosableInteger * maxChoosableInteger)
Space Complexity: O(2^maxChoosableInteger)
Solution
We use a recursive DFS approach with memoization to track the winning possibilities from each state. A bitmask (or integer state) is used to represent which numbers have been picked so far. The recursion simulates each move by subtracting the chosen number from the desired total. If a move results in a win (i.e., chosen number >= remaining total) or forces the opponent into a position where they cannot win, then we mark the state as winning for the current player. We store already computed states in a memo dictionary to avoid redundant computation.