Problem Description
Given a tree with n nodes (numbered 0 to n-1) and an edge list representing its structure, you are provided with several queries. Each query consists of three integers: start, end, and target. For each query, you need to determine the node along the unique path from start to end that is closest (in terms of shortest path distance in the tree) to the target node.
Key Insights
- The tree structure guarantees a unique simple path between any two nodes.
- The first challenge is to extract the path from start to end; this can be done using a DFS or BFS since the tree is undirected.
- Once the path is determined, we must find the node from this path that minimizes the distance to the query target node.
- For finding distances in the tree (which is unweighted), a BFS starting from the target node provides the shortest distances to all nodes.
- Given the constraints (n, number of queries ≤ 1000), a solution that performs DFS to find the path and BFS for each query is efficient enough.
Space and Time Complexity
Time Complexity: O(m * n) where m is the number of queries and n is the number of nodes. Each query may require a DFS (to find the path) and a BFS (to compute distances from the target) over the tree. Space Complexity: O(n) to store the graph and additional O(n) for recursion/BFS queues per query.
Solution
We first build an adjacency list for the tree from the given edges. For each query, we follow these steps:
- Use DFS to find and record the unique path from the start node to the end node.
- Use BFS starting from the target node to calculate the shortest distance from the target to every other node in the tree.
- Iterate over the nodes in the obtained path and select the node having the minimum distance to the target.
- Return the selected node as the answer for that query.
This approach leverages both DFS and BFS techniques and takes advantage of the tree’s properties (unique paths) to solve the problem directly.