Problem Description
You are given two arrays, arr1 and arr2, containing positive integers. A prefix of a positive integer is formed by one or more of its digits starting from the leftmost digit. A common prefix of two integers is a number that is a prefix of both. The task is to find the length of the longest common prefix among all pairs (x, y) such that x is from arr1 and y is from arr2. If no common prefix exists among any such pair, return 0.
Key Insights
- Convert each integer into its string representation to easily extract and compare prefixes.
- For any integer, you can derive all possible prefixes (e.g., "12345" gives "1", "12", "123", "1234", "12345").
- Instead of comparing every pair (which would be inefficient), generate a set of all prefixes for arr1 and another set for arr2, then find the intersection of these sets.
- The result is the maximum length among all common prefixes.
Space and Time Complexity
Time Complexity: O((n + m) * d), where n and m are the lengths of arr1 and arr2 respectively, and d is the maximum number of digits (at most 9).
Space Complexity: O((n + m) * d) for storing all prefixes in sets.
Solution
The approach involves converting the numbers in each array into strings and generating all possible prefixes for each number. We then store these prefixes in two sets (one for each array) and compute the intersection to obtain the common prefixes. The length of the longest prefix in this intersection is the answer. This method avoids checking every pair individually and leverages set operations for efficiency.