Problem Description
Given an array of digits (0-indexed) where each element is between 0 and 9, repeatedly form a new array by adding each pair of adjacent elements and taking the sum modulo 10. This process continues until only one element remains. The final single element is the triangular sum of the array.
Key Insights
- The operation involves pairwise addition of adjacent elements modulo 10.
- The process simulates reduction of the array until only one value remains.
- Each reduction step decreases the array size by one, leading to a quadratic time behavior in the worst case.
- Although there is a combinatorial formula involving binomial coefficients, simulation is straightforward given the constraint sizes.
Space and Time Complexity
Time Complexity: O(n^2) in the worst-case scenario due to iterative pairwise reductions. Space Complexity: O(n) extra space to store the new array at each iteration.
Solution
We simulate the process of forming new arrays until only one element remains. At each step, we iterate through the current array and form a new array where each element is the sum of two adjacent elements modulo 10. The key data structure is the array itself, and the primary algorithmic approach is iterative simulation. This approach is efficient enough given the constraints, and it directly mirrors the problem description.