Problem Description
Given an integer array nums, determine whether there exists a triplet of indices (i, j, k) such that i < j < k and nums[i] < nums[j] < nums[k]. Return true if such a triple exists; otherwise, return false.
Key Insights
- You are asked to find three numbers in increasing order.
- The goal is to achieve this in O(n) time and O(1) space.
- Maintaining two variables for the smallest and second smallest numbers found so far allows checking if a greater third number exists.
- Each element is compared to update these candidates based on a greedy approach.
Space and Time Complexity
Time Complexity: O(n) — traverse the list once
Space Complexity: O(1) — only constant extra space is used
Solution
The algorithm scans through the array while keeping two variables: "first" representing the smallest value encountered so far and "second" for the next smallest value greater than "first". For each number:
- If it is less than or equal to "first", update "first".
- Else if it is less than or equal to "second", update "second".
- Otherwise, a valid triplet is found and the function returns true. This efficient approach uses the greedy method to maintain candidates for the first two numbers and automatically finds a valid third number if it exists.