Problem Description
Given a binary array nums and an integer k, the task is to determine the maximum number of consecutive 1's in the array after flipping at most k zeros to 1's.
Key Insights
- The problem can be solved efficiently using the sliding window technique.
- Maintain a window that can contain at most k zeros.
- When the number of zeros in the window exceeds k, move the left pointer to shrink the window.
- Record the maximum window length during the iteration which gives the maximum consecutive ones.
Space and Time Complexity
Time Complexity: O(n), where n is the length of the array, since we process each element at most once. Space Complexity: O(1), only constant extra space is used.
Solution
We use a sliding window approach:
- Use two pointers (left and right) that define the current window.
- Traverse the array using the right pointer.
- Count the number of zeros encountered in the current window.
- When the count exceeds k, increment the left pointer until there are at most k zeros in the window.
- Throughout the process, the length of the current valid window is recorded, and the maximum window length is updated.
- The maximum window length gives the maximum number of consecutive 1's achievable with at most k flips.