Problem Description
Given a 0-indexed integer array nums, select two integers from the array such that they form a strong pair. A pair (x, y) is defined as strong if |x - y| <= min(x, y). The goal is to find the maximum possible bitwise XOR value among all strong pairs. Note that you are allowed to choose the same integer twice to form a pair.
Key Insights
- A pair (x, y) is strong if the absolute difference between x and y does not exceed the smaller of the two numbers.
- Self pairs, where both numbers are the same, always satisfy the condition (since 0 <= x).
- Given the small constraints (nums.length <= 50), brute force checking of all pairs is efficient.
- The XOR operation is straightforward and any valid pair’s XOR can be computed directly.
- Brute force solution involves iterating over all possible pairs and updating a maximum value when conditions are met.
Space and Time Complexity
Time Complexity: O(n²), where n is the number of elements in nums, due to the nested iteration over pairs. Space Complexity: O(1), as no extra space apart from a few variables is used.
Solution
The problem can be solved by checking every possible pair in the array. For every pair (x, y), we verify that the strong pair condition |x - y| <= min(x, y) holds. If it does, we compute the XOR of x and y and update our maximum result if this XOR is greater than the current maximum. This exhaustive search is feasible given the small input size.