Problem Description
Given an integer array nums and two integers limit and goal, find the minimum number of elements you need to add to nums so that its sum equals goal. All numbers (original and added) must satisfy abs(x) <= limit.
Key Insights
- Compute the current sum of nums.
- Determine the absolute difference between goal and the current sum.
- Each added element can contribute at most limit (in absolute value) to reducing the difference.
- The minimum number of elements needed is given by the ceiling of (difference / limit).
Space and Time Complexity
Time Complexity: O(n), where n is the length of nums (to compute the sum)
Space Complexity: O(1)
Solution
The solution involves first calculating the current sum of the array. Then, the difference (diff) between the goal and this sum is found and its absolute value is used. Since each inserted number can add at most limit to reduce this gap, the minimum number of elements is computed by taking the ceiling of diff divided by limit. This is efficiently done using the formula (diff + limit - 1) // limit, which handles the rounding up when diff is not exactly divisible by limit.