Problem Description
Given an integer num, return the number of steps required to reduce it to zero. In each step, if the number is even, divide it by 2; if the number is odd, subtract 1.
Key Insights
- If the number is even, dividing by 2 quickly reduces its size.
- If the number is odd, subtracting 1 makes it even, allowing the next division operation.
- The process repeats until the number becomes zero.
- The problem can be implemented using iterative or recursive approaches with a simple loop.
Space and Time Complexity
Time Complexity: O(log n)
Space Complexity: O(1)
Solution
We use a loop that repeatedly checks if the current number is even or odd.
- If it is even, we divide by 2, utilizing the property of binary numbers where division by 2 is equivalent to a bit right shift.
- If it is odd, we subtract 1 to make it even.
The primary data structure is a simple integer counter to track the number of steps. The algorithm directly manipulates the integer with arithmetic operations without requiring any additional data structures.