Problem Description
In this problem, we are given an array of answers from rabbits in a forest. Each rabbit is asked how many other rabbits share his/her color. Using these responses, we want to determine the minimum total number of rabbits in the forest, accounting for rabbits that did not answer.
Key Insights
- Use a hash table (or dictionary) to count the frequency of each answer.
- For an answer x (meaning the rabbit sees x other rabbits of the same color), the group size is (x + 1) because the rabbit himself/herself is included.
- For each unique answer, calculate the number of groups needed as the ceiling of (frequency / (x + 1)).
- Multiply the number of groups by the group size (x + 1) and sum this value for all unique answers to obtain the minimum total number of rabbits.
Space and Time Complexity
Time Complexity: O(n), where n is the number of elements in the answers array. Space Complexity: O(n) in the worst case due to the hash table storing counts for each distinct answer.
Solution
The solution leverages a greedy approach:
- Traverse the answers array once to count the occurrences of each answer using a hash table.
- For each distinct answer x with frequency count, compute the number of groups required as:
- groups = ceil(count / (x + 1))
- The contribution of each distinct answer to the total count is groups multiplied by the group size (x + 1).
- Sum these contributions to get the minimum total number of rabbits.
The essential trick is understanding that if a rabbit says x, there must be a full group size of (x + 1), and even if not all rabbits in a potential group answered, we still must account for the full group.