Problem Description
Given an integer array nums, rotate the array to the right by k steps, where k is non-negative. In other words, move the last k elements to the front of the array while preserving their order.
Key Insights
- The rotation amount k might be greater than the length of the array, so use k % n (where n is the array length) to compute the effective rotation.
- A smart in-place solution involves reversing sections of the array:
- Reverse the entire array.
- Reverse the first k elements.
- Reverse the remaining n-k elements.
- Alternative approaches include using extra space or performing k single-step rotations (which is less optimal).
Space and Time Complexity
Time Complexity: O(n) where n is the number of elements in the array. Space Complexity: O(1) if done in-place.
Solution
We solve the problem using the "reverse" technique to perform the rotation in-place. First, we adjust k by taking k modulo the length of the array to handle cases where k exceeds the array length. Then, we reverse the entire array. Next, we reverse the first k elements to restore their correct order. Finally, we reverse the remaining n-k elements. This sequence yields the array rotated to the right by k positions while strictly using O(1) extra space.