Problem Description
Given an integer array nums, define the rotation function F for an array rotation arrₖ (rotating nums by k clockwise) as:
F(k) = 0 * arrₖ[0] + 1 * arrₖ[1] + ... + (n - 1) * arrₖ[n - 1].
The goal is to compute and return the maximum value among F(0), F(1), ..., F(n-1).
Key Insights
- Calculate the total sum S of the array and the initial function value F(0).
- Derive the recurrence: F(k+1) = F(k) + S - n * element_moved, where element_moved is the element that transitions from the end to the front.
- This recurrence helps compute F for each rotation in O(n) time, avoiding an O(n²) recalculation.
Space and Time Complexity
Time Complexity: O(n)
Space Complexity: O(1)
Solution
We start by computing the sum of all elements (S) and F(0) by summing i*nums[i] for all indices. To derive F(k+1) from F(k), observe that when the array is rotated, each element's contribution increases by its value (total S), while the element shifted from the end to the front loses its original weighted contribution (n times its value). This observation forms the recurrence relation, allowing us to update the function value in O(1) time per rotation and track the maximum value.