Problem Description
Given a mapping of digits (0-9) and an array of numbers, each digit of every number is replaced by its mapped counterpart. The resulting mapped value (interpreted as an integer that ignores any leading zeros) is used as a sorting key. The task is to sort the original numbers based on these mapped values in non-decreasing order while keeping the relative order of numbers with equal mapped values.
Key Insights
- Create a helper function that converts an integer by mapping each of its digits using the provided mapping.
- Convert the resulting mapped string into an integer to ignore any leading zeros.
- Use a stable sorting algorithm so that numbers with the same mapped value maintain their relative order.
- The transformation process adds only a constant factor since each number has at most 10 digits (given the constraint of numbers up to 10^9).
Space and Time Complexity
Time Complexity: O(n * d + n log n), where n is the number of elements in nums and d is the number of digits (at most 10).
Space Complexity: O(n), for storing the mapped values during the sort.
Solution
We first define a helper function that takes a number and returns its mapped value by iterating through its digits. For each digit, we look up its mapped counterpart and join them to form a new string, which is then converted to an integer (this conversion naturally removes any leading zeros). We then sort the original array of numbers using these mapped values as sorting keys. The sort must be stable, so that if two numbers have the same mapped value, their order relative to each other remains unchanged.
Data structures used include:
- A string to build the mapped representation for each number.
- An integer for the converted mapped value.
The algorithmic approach involves:
- Mapping each number to its transformed value.
- Performing a stable sort based on these transformed values.
- Returning the original numbers arranged in sorted order based on their mapped values.