Problem Description
Given an integer n in base 10 and a base k, convert n from base 10 to base k and then compute the sum of the digits of the resulting number. The digits should be interpreted as base 10 numbers when summing.
Key Insights
- Convert the number from base 10 to base k by repeatedly dividing by k and recording the remainder.
- The remainders from each division represent the digits of the number in base k.
- Sum the digits (as base 10 values) once the conversion is complete.
- The constraint sizes are small, so a simple iterative approach is sufficient.
Space and Time Complexity
Time Complexity: O(log_k(n)) – The number of divisions needed is proportional to the number of digits in the new base. Space Complexity: O(1) – Only a few integer variables are used, and the sum can be computed on the fly.
Solution
We solve the problem by converting n from base 10 to base k using iterative division. In each iteration, we calculate the remainder (which becomes one digit in base k) and add it directly to a running sum. This avoids the need to store the full representation of the number. Once n is reduced to 0, the sum of all the digits (as computed by the remainders) is the answer. The approach leverages basic arithmetic operations and a loop, making it both efficient and easy to understand.